很久之前写的了，好像是对拍打表过的，推一下就行了。

 

#include 
     
      using namespace std;typedef long long ll;int main(){    ll a,b,c;    scanf("%lld%lld%lld",&a,&b,&c);    ll ans=c*3;    if((a>=1&&b>=1)||(a>=2))    printf("%lld\n",ans+a+b*2);    else if(a==0&&b==0)    printf("%lld\n",c);    else if((a==0&&b==1)||(a==1&&b==0))    printf("%lld\n",c*2+1);    else if(b==0)    printf("%lld\n",c);    else if(c==0)    printf("%lld\n",b);    else    printf("%lld\n",c*3+b*2-2);    return 0;}